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Power Formula:
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The torque RPM power formula calculates mechanical power output from torque and rotational speed. This fundamental engineering equation is widely used in automotive, mechanical engineering, and industrial applications to determine horsepower.
The calculator uses the power formula:
Where:
Explanation: The constant 5252 comes from the relationship between horsepower, torque, and RPM, where 1 horsepower equals 550 foot-pounds per second, and there are 60 seconds in a minute.
Details: Accurate power calculation is essential for engine performance analysis, mechanical system design, vehicle specifications, and industrial machinery optimization. It helps engineers understand the relationship between torque and rotational speed.
Tips: Enter torque in lb-ft and RPM in revolutions per minute. Both values must be positive numbers. The calculator will automatically compute the power in horsepower.
Q1: Why is the constant 5252 used in this formula?
A: The constant 5252 comes from unit conversions where 1 horsepower = 550 foot-pounds per second and there are 60 seconds in a minute (550 × 60 ÷ 2π ≈ 5252).
Q2: Can this formula be used for metric units?
A: For metric units, use P = (T × RPM) / 9549, where T is in Newton-meters and P is in kilowatts.
Q3: What is the relationship between torque and horsepower?
A: Torque represents rotational force, while horsepower represents work done over time. At 5252 RPM, torque and horsepower values are always equal.
Q4: Why do engines have peak torque and peak power at different RPMs?
A: Engines produce maximum torque at lower RPMs where volumetric efficiency is highest, while maximum power occurs at higher RPMs where the product of torque and RPM is maximized.
Q5: How accurate is this formula for real-world applications?
A: This formula provides theoretical mechanical power. Actual power output may vary due to mechanical losses, efficiency factors, and other real-world conditions.